1345. Leetcode solution in Java

class Solution {
    public int minJumps(int[] arr) {
        if (arr.length == 1)
            return 0;
        int count = 0;
        int length = arr.length;
        Map<Integer, List<Integer>> graph = new HashMap<>();
        // populate the graph with index
        for (int i=0; i<length; i++)
            graph.computeIfAbsent(arr[i], x->new LinkedList<>()).add(i);
        // create the boolean array visited
        boolean [] visited = new boolean [length];
        // mark the first element as visited
        visited[0] = true;
        // since we do bfs, we need a queue
        Queue<Integer> queue = new LinkedList<>();
        queue.offer(0);
        while (!queue.isEmpty()) {
            int size = queue.size();
            for (int i=size; i>0; i--) {
                int current = queue.poll();
                // if we reach the last index
                if (current == length - 1)
                    return count;
                // get the possible next values
                List<Integer> next = graph.get(arr[current]);
                // now lets add the previous, ie current-1, next ies, current + 1 into the list
                next.add(current-1);
                next.add(current+1);
                for (Integer j:next) {
                    if (j >= 0 && j<length && !visited[j]) {
                        visited[j] = true;
                        queue.offer(j);
                    }
                }
                next.clear(); 
            }
            count += 1;
        }
        return 0;
    }
}