re: JavaScript Closure Simply Explained VIEW POST


Hi Phillip,

Thank you for writing this great article on closures. The practical examples are easy to understand.

I wonder how, in the last example of the for loop, could you refactor the example so that each index prints out after the setTimeout value has elapsed

Like this:
0 (...1000ms have passed)
1 (...1000ms have passed)
2 (...1000ms have passed)
3 (...1000ms have passed)
4 (...1000ms have passed)
5 (loop exits)


I see that you made the edit!

But that is not actually what happens when you run the code.

The code you wrote prints 0-4 (all indexes) after 2000ms all at once.

I was curious how to make a loop that prints out each index, one at a time, according to the setTimeout value.

Maybe this isn't possible using a for loop.

I hope that makes sense!!

They print all at once because all setTimeout starts at same time and for all setTimeout 1 second passes at same time. What you want can be achieved by passing timeout values to 1000, 2000, 3000....

Following code will give you that output:

for(var i=0; i<5; i++) {
  setTimeout((function(index) {
    return function() {
  }(i)), 1000 * i)
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