Want another challenge? Try implementing all of the Enumerable methods using only reduce. It should be noted that the signature for reduce / inject takes an initial value and does not necessarily assume the first item as the initial accumulator.
As an aside, any? / none? do not iterate every element. They break the second they find an element for which the condition is true where any? returns true and none? returns false.
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Want another challenge? Try implementing all of the
Enumerablemethods using onlyreduce. It should be noted that the signature forreduce/injecttakes an initial value and does not necessarily assume the first item as the initial accumulator.As an aside,
any?/none?do not iterate every element. They break the second they find an element for which the condition istruewhereany?returnstrueandnone?returnsfalse.