Shortest answer I could think of:
const horses = n => { if(Number.isInteger(n)) return n < 3 ? n : n * (n-1) * (n-2) };
And in Standard ML, since it has type checking I can skip the int check:
fun horses(n: int) : int = if n < 3 then n else n * (n - 1) * (n - 2)
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Shortest answer I could think of:
And in Standard ML, since it has type checking I can skip the int check: