Hi, I am Amit Shekhar, Co-Founder @ Outcome School • IIT 2010-14 • I have taught and mentored many developers, and their efforts landed them high-paying tech jobs, helped many tech companies in solving their unique problems, and created many open-source libraries being used by top companies. I am passionate about sharing knowledge through open-source, blogs, and videos.
In this blog, we are going to learn about the advantage of using const
in Kotlin.
It is one of the commonly asked questions during the Android Interview.
This article was originally published at Outcome School.
The best way to learn this is by taking an example.
Assume that we have a class MyClass
in Kotlin.
class MyClass {
companion object {
const val FILE_EXTENSION = ".png"
val fileName:String
get() = "Img_" + System.currentTimeMillis() + FILE_EXTENSION
}
}
Now, we need to decompile this code. For that, we will have to convert this Kotlin source file to a Java source file.
Steps to convert from Kotlin source file to Java source file and decompile in Android Studio:
-
Tools
>Kotlin
>Show Kotlin Bytecode
. You will get the bytecode of your Kotlin file. - Now click on the
Decompile
button to get your Java code from the bytecode.
We will get the following:
public final String getFileName() {
return "Img_" + System.currentTimeMillis() + ".png";
}
Here, I have kept only the important lines of the code and removed other lines for brevity.
Here, we can see that the variable FILE_EXTENSION
has been replaced by its value which is .png
.
As the value has been inlined, there will be no overhead to access that variable at runtime. And hence, it will lead to a better performance of the application.
This is the advantage of using const
in Kotlin.
That's it for now.
Check: Android System Design Interviews
Thanks
Amit Shekhar
Co-Founder @ Outcome School
You can connect with me on:
Top comments (0)