Not too elegant, but a compact and efficient one-liner, using Python 3.8's assignment expressions.
solve = lambda s: (ord_list := list(map(ord, s))) and max(ord_list) - min(ord_list) == len(s) - 1 for case in ['abc', 'abd', 'dabc', 'abbc', 'v', 'zyx', 'azj']: print(f'{case}: {solve(case)}')
Try it online!
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Not too elegant, but a compact and efficient one-liner, using Python 3.8's assignment expressions.
Try it online!