Abdulla Ansari

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# Subtract the Product and Sum of Digits of an Integer | Leetcode

Hey coders welcome to our new series of solving programming questions. So we are back with Leet Code solution in C++ and Python, so let's start.

Problem Statement
Given an integer number n, return the difference between the product of its digits and the sum of its digits.

Example 1:

```Input: n = 234 Output: 15 Explanation: Product of digits = 2 * 3 * 4 = 24 Sum of digits = 2 + 3 + 4 = 9 Result = 24 - 9 = 15```

Example 2:
```Input: n = 4421 Output: 21 Explanation: Product of digits = 4 * 4 * 2 * 1 = 32 Sum of digits = 4 + 4 + 2 + 1 = 11 Result = 32 - 11 = 21```

C++ Solution

``````class Solution {
public:
int subtractProductAndSum(int n) {
int sum = 0;
int product = 1;

while(n != 0){
int digit = n % 10;
sum += digit;
product = product * digit;
n = n / 10;
}

int subtract = product - sum;
return subtract;
}
};
``````

Python3 Solution

``````

def subtractProductAndSum(n):
sums = 0
product = 1

while(n != 0):
digit = n % 10
sums += digit
product = product * digit
n = n // 10

return (product - sums)

print(subtractProductAndSum(234))
``````

So this was the simplest solution for this problem you can also try different approaches to solve this problem in a efficient way.

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