A bit like @nicolas Hervé, using the reduce method:
reduce
f=a=>[...a].reduce((t,l)=>t+l.charCodeAt``-96,0)
[...a]
["l", "o", "v", "e"]
96
"a"
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A bit like @nicolas Hervé, using the
reducemethod:[...a]transforms the string to an array with every character (["l", "o", "v", "e"])reducemethods will loop through every character, get its charCode, subtract96to it (the charCode associated with"a"+ 1), and sum everything