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Discussion on: Daily Challenge #71 - See you next Happy Year

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vinniew1rus profile image
Vinnie •

Simple JS solution:

function nextHappyYear(year){
    let newYear = year + 1;
    let arr = newYear.toString().split('');
    let uniq = arr.filter((item, pos) => arr.indexOf(item) == pos);
    if (uniq.length !== arr.length)
        return nextHappyYear(newYear);
    return newYear;
}
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vinniew1rus profile image
Vinnie • • Edited

And a PHP solution:

function nextHappyYear($year){
    $newYear = $year+1;
    return strlen($newYear) == count(array_unique(str_split($newYear))) ? $newYear : nextHappyYear($newYear);
}