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Pure virtual functions and binary compatibility (4 answers)
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(Private feedback for you)
I have a abstract base class . There are many abstract classes which derived from this Abstract Base class
class Base
{
public:
virtual void food() =0
};
for example
class Derived1: public Base
{
};
Suppose i want to add new method to it, without breaking binary compatibility. The only way is to extend this class
class Base_Ext : public Base
{
public:
virtual void food1()=0;
};
The problem is the already existing derived classes implementation wont be able to access this food1(). How to solve this problem How can Abstract Derived classes see this new method
One solution i have in mind is : - Lets say the original Derived class was Derived1......
class Derived1: public Base
{
} ;
Now i would need to extend Derived1.......
class Derived2 : public Derived1, public Base_Ex
{
} ;
again here to solve diamond problem, I will have to change
class Derived1: public Base to
class Derived1: public virtual Base {}
which i dont want to do.. as it would again break binary compatibility of existing derived classes.so stuck at it
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