JavaScript:
const spreadNumber = n => [...Array(n).keys()]
I think you have an off-by-one error: spreadNumber(2) gives [0, 1] instead of [1, 2]. Nice and concise, though!
spreadNumber(2)
[0, 1]
[1, 2]
Thanks. I didnt notice its zero based
That creates an Array from 0 to n not from 1 to n ;-)
const spreadNumber = n => Array(n).fill(0).map((_, i) => i+1);
Yeah, i didnt notice its not zero based
Another way:
const spreadNumber = n => Array.from({length:n}).map((_, i) => i+1);
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JavaScript:
I think you have an off-by-one error:
spreadNumber(2)gives[0, 1]instead of[1, 2]. Nice and concise, though!Thanks. I didnt notice its zero based
That creates an Array from 0 to n not from 1 to n ;-)
const spreadNumber = n => Array(n).fill(0).map((_, i) => i+1);Yeah, i didnt notice its not zero based
Another way: