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# Java Program to Print Square Pattern Star Pattern

Sachin Ponnapalli

Program to Print Square Star Pattern
In this article we are going to see how to print the square  star program.

```Example-1

When row value=4
****
****
****
****```
```Example-2:

When row value=5
*****
*****
*****
*****
*****```
Now, let's see the actual program to print it. Approach:
• Enter total row and store it in an integer variable `row`.
• Take first for loop to print all rows.
• Take second/inner for loop to print column values.
• Then go on printing the star symbols according to the iteration.
JAVA Code:

### Method-1 : Static Star Pattern

```import java.util.*;
public class Main
{
public static void main(String args[])
{   // taking variable for loop iteration and row .
int row,r,c,d;
//creating object
Scanner s = new Scanner(System.in);
// entering the number of row
System.out.print("Enter rows : ");
row = s.nextInt();
//for loop for rows
for(  r=0;r<row;r++)
{
// printing stars
for( c=0;c<row;c++)
System.out.print("*");
System.out.println();
}
}
}

```
```Output:

Enter rows : 5
*****
*****
*****
*****
*****```

### Method-2 : User Input Pattern

```import java.util.*;
public class Main
{
public static void main(String args[])
{   // taking variable for loop iteration and row .
int row,r,c,d;
//creating object
Scanner s = new Scanner(System.in);
// entering the number of row
System.out.print("Enter rows : ");
row = s.nextInt();
// entering any character
System.out.print("Enter any character : ");
char sym = s.next().charAt(0);
//for loop for rows
for(  r=0;r<row;r++)
{
// printing stars
for( c=0;c<row;c++)
System.out.print(sym);
System.out.println();
}
}
}

```
```Output:

Enter rows : 5
Enter any character : #
#####
#####
#####
#####
#####```
Explanation : Let's understand the program by going through the detailed explanation. We have taken row value as 5. Iteration-1 r=0 (passes the first for loop condition) because it will execute until `r< row` Star will be printed 5 time because inner for loop will be executed `row` time .
`*****`
Iteration-2 r=1 (passes the first for loop condition) because it will execute until `r< row` Star will be printed 5 time because inner for loop will be executed `row` time .
`*****`
Iteration-3 r=2 (passes the first for loop condition) because it will execute until `r< row` Star will be printed 5 time because inner for loop will be executed `row` time .
`*****`
Iteration-4 r=3 (passes the first for loop condition) because it will execute until `r< row` Star will be printed 5 time because inner for loop will be executed `row` time .
`*****`
Iteration-5 r=4 (passes the first for loop condition) because it will execute until `r< row` Star will be printed 5 time because inner for loop will be executed `row` time .
`*****`
Now i=5, so first for loop condition will fail.  So next for loop will not be executed any more. Now, after end of all iteration we will see the complete pattern is printed on the output screen like this.
```*****
*****
*****
*****
*****```
C Code:
```#include <stdio.h>
int main() {
int r, row, c ,d;
printf("Enter rows: ");
scanf("%d", &row);
for(  r=0;r<row;r++)
{
// printing stars
for( c=0;c<row;c++)
printf("*");
printf("\n");
}
return 0;
}

```
```Output:

Enter rows : 5
*****
*****
*****
*****
*****```
C++ Code:
```#include <iostream>
using namespace std;
int main()
{
int row, r , c ,d ;
cout << "Enter  rows: ";
cin >> row;
for(  r=0;r<row;r++)
{
// printing stars
for( c=0;c<row;c++)
cout<< "*" ;
cout << "\n" ;
}
return 0;
}
```
```Output:

Enter rows : 5
*****
*****
*****
*****
*****```