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Discussion on: Daily Challenge #124 - Middle Me

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Rafael Acioly

Nice! just a hint, if you have a return inside the first if you don't need the else ;)

Here's my solution:

def middle_me(middle: str, repeat: str, repeat_quantity: int) -> str:
  if repeat_quantity % 2 != 0:
    return middle

  half = repeat_quantity // 2
  content = repeat * repeat_quantity
  return content[:half] + middle + content[half:]