You have to await Q and then execute .json() on the result. fetch() returns a promise that can be awaited.
await Q
.json()
fetch()
Would probably go for something like:
let Q = await fetch('/ajax/get', { method: 'POST', body: FD }); let data = await Q.json();
Read 4th parahraph under Concepts and usage: developer.mozilla.org/en-US/docs/W...
Thank you, just noticed. In a hurry forgot to specify await
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You have to
await Qand then execute.json()on the result.fetch()returns a promise that can be awaited.Would probably go for something like:
Read 4th parahraph under Concepts and usage:
developer.mozilla.org/en-US/docs/W...
Thank you, just noticed. In a hurry forgot to specify await