I guess what I am getting it as if you had an array called xs and you called map on that array, would you in effect be calling Array.prototype.map.call(xs,function)? Since map doesnβt belong to xs. I know I am being very specific here π
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I guess what I am getting it as if you had an array called xs and you called map on that array, would you in effect be calling Array.prototype.map.call(xs,function)? Since map doesnβt belong to xs. I know I am being very specific here π