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Discussion on: Daily Challenge #35 - Find the Outlier

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peter279k

Here is the simple solution with PHP:

function find($integers) {
  $evenArray = [];
  $oddArray = [];

  foreach ($integers as $integer) {
    if ($integer % 2 === 0) {
      $evenArray[] = $integer;
    } else {
      $oddArray[] = $integer;
    }
  }

  if (count($evenArray) === 1) {
    return $evenArray[0];
  }

  return $oddArray[0];
}