Discussion on: JavaScript Programming Problem 2

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I learn from wise guy: fun-fun-function reduce is a swish knife of functional programming, in this case:

[..."3123dasds JJKH e o a eee iJ"].reduce( 
 (coll, chr) => coll[chr] 
   ? {...coll, [chr]: coll[chr] + 1} 
   : {...coll, [chr]:1 }
, {});

Muhammad Hamza Hijazi • Oct 25 '20

this function is counting all alphabets in string.

Peter Vivo • Oct 26 '20

you right!

to work with vowels need filter before this process:


const countChars =  
 (coll, chr) => coll[chr] 
   ? {...coll, [chr]: coll[chr] + 1} 
   : {...coll, [chr]:1 };

const vowels = "aeiouóöőüúűáé"; // hungarian vowels included

const filterWovels = chr => vowels.indexOf(chr) > -1;

const vowelCount = s => [...s.toLowerCase].filter(filterWovels).reduce(countChars, {});