Hmm... As a bootcamp student, I'm trying to untangle this.
[!(offsetIndex % 3) + 0]
I see this checks the modulus, and inverts the result. Any non-zero int is truthy, and this expression makes it false . . . +0 to coerce the false to an int. That is enough that the entire thing evaluates falsy, which then results in outputting offsetIndex on the otherside of the or. I had to drop this in a node repl to follow it, but I eventually got it š
But what is the ["", "Fizz"][!(offsetIndex % 3) + 0] double-array looking thing there? I thought it was a 2d array at first, but that doesn't seem right for a number of reasons.
I'm pretty sure the first pair of square brackets creates an array, and the second one indexes into that array. So I think they are array indexing into the first array with either 0 or 1 to pick the empty string or "Fizz" depending on the offsetIndex!
yup, it defines the array first const array = ["", "Fizz"] and then access the index array[!(offsetIndex % 3) + 0]. The expression will resolve either to true+0 -> 1 or false+0 -> 0
I THOUGHT it might have been something like that, but I was thinking about it wrongly . . . I wasn't thinking of it as the array followed by the index, I was thinking of it as a variable. So ["an", "array"] was the name of the array, and then it had it's own index. Not very practical.
But the actual use is quite cool and makes plenty sense.
Thanks!
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Hmm... As a bootcamp student, I'm trying to untangle this.
[!(offsetIndex % 3) + 0]I see this checks the modulus, and inverts the result. Any non-zero int is truthy, and this expression makes it false . . .
+0to coerce thefalseto an int. That is enough that the entire thing evaluates falsy, which then results in outputtingoffsetIndexon the otherside of theor. I had to drop this in a node repl to follow it, but I eventually got it šBut what is the
["", "Fizz"][!(offsetIndex % 3) + 0]double-array looking thing there? I thought it was a 2d array at first, but that doesn't seem right for a number of reasons.I'm pretty sure the first pair of square brackets creates an array, and the second one indexes into that array. So I think they are array indexing into the first array with either 0 or 1 to pick the empty string or "Fizz" depending on the offsetIndex!
Hope that helps!
yup, it defines the array first
const array = ["", "Fizz"]and then access the indexarray[!(offsetIndex % 3) + 0]. The expression will resolve either totrue+0 -> 1orfalse+0 -> 0holy shit. that's cool.
I THOUGHT it might have been something like that, but I was thinking about it wrongly . . . I wasn't thinking of it as the array followed by the index, I was thinking of it as a variable. So
["an", "array"]was the name of the array, and then it had it's own index. Not very practical.But the actual use is quite cool and makes plenty sense.
Thanks!