In this question we are asked to Return Largest Numbers in Arrays.
Tests that we should pass
largestOfFour([[4, 5, 1, 3], [13, 27, 18, 26], [32, 35, 37, 39], [1000, 1001, 857, 1]]) should return an array.
largestOfFour([[13, 27, 18, 26], [4, 5, 1, 3], [32, 35, 37, 39], [1000, 1001, 857, 1]]) should return [27, 5, 39, 1001].
largestOfFour([[4, 9, 1, 3], [13, 35, 18, 26], [32, 35, 97, 39], [1000000, 1001, 857, 1]]) should return [9, 35, 97, 1000000].
largestOfFour([[17, 23, 25, 12], [25, 7, 34, 48], [4, -10, 18, 21], [-72, -3, -17, -10]]) should return [25, 48, 21, -3].
First answer
function largestOfFour(arr) {
let maxInSubArr=0
let newArr=[]
for(let i=0;i<arr.length;i++){
for (let j=0;j<arr[i].length;j++){
if(maxInSubArr<arr[i][j]){
maxInSubArr=arr[i][j]
}
}
newArr.push(maxInSubArr)
maxInSubArr=0
}
return newArr;
}
Second answer
function largestOfFour(arr) {
let newArr=[]
for(let i=0;i<arr.length;i++){
let maxInSubArr = arr[i][0];
for (let j=0;j<arr[i].length;j++){
if(maxInSubArr<arr[i][j]){
maxInSubArr=arr[i][j]
}
}
newArr.push(maxInSubArr)
}
return newArr;
}
Correct Answer is Answer 2, reason being, in the first answer we do not handle negative numbers, we set it to zero initially then reset it to zero once its pushed to return array, however in the second solution we are setting it to the first item in subarray
Latest comments (1)
If you want to have a 1-liner using modern JS:
For super large arrays it's recommended to convert it in a Float typed array to speed up sorting by up to 5X times! see: stackoverflow.com/a/53355543/1059828