Third times the charm, day 3 of #100daysofcode. For day 3 of coding I got to work on an interesting little code project called caser cipher. My initial experience with this problem was interesting since I was on good roll breezing through these problems until I had to do this. It was mixture of self doubt and excitement, on the one hand I'm struggling with a simple problem but at the same time it means I have to push myself to figure out what I need to do to solve this. Through a mixture of StackOverFlow and re-watching videos, I was able to solve this problem. I'm so proud of my solution that I will post this snippet on my post.
alphabet = ['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z', 'a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z']
def cesar(start_text,shift_amount,cipher_direction):
end_text = ""
if cipher_direction.lower() == "decode":
shift_amount *= -1
for char in start_text:
end_text += alphabet[alphabet.index(char)+shift_amount]
elif cipher_direction.lower() == "encrypt":
for char in start_text:
end_text += alphabet[alphabet.index(char)+shift_amount]
else:
print("Incorrect")
print(end_text)
cesar("hello",5,"encrypt")
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