Here's my TypeScript version.
This approach works in O(n) by dividing the product of all elements by x[i].
x[i]
function uberMultiply(x: Array<number>) { const product = x.reduce( (a,b) => a * b ); return x.map(v => product / v); }
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Here's my TypeScript version.
This approach works in O(n) by dividing the product of all elements by
x[i]
.