JavaScript challenges_1 🐲

Array.diff

• Your goal in this kata is to implement a difference function.
• Which subtracts one array from another and returns the result.
• It should remove all values from array [a].
• Which are present in array [b] keeping their order.

Examples:

• arrayDiff([1,2],[1]) == [2]

• If a value is present in b,

• All of its occurrences must be removed from the other:

• ArrayDiff([1,2,2,2,3],[2]) == [1,3]

Task URL

My solution:

let arr1 = [1, 2, 2, 2, 3];
let arr2 = [2];

function arrayDiff(a, b) {
    let result = []
    for (let i = 0; i < a.length; i++) {
        if (b.indexOf(a[i]) === -1) {
            result.push(a[i])
        }
    }
    return result;
}
console.log(arrayDiff(arr1, arr2))

// Output
[ 1, 3 ]