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Discussion on: Solving the FizzBuzz Interview Question with JavaScript

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jonrandy profile image
Jon Randy 🎖️ • • Edited

Here are some more (I omitted the console logging though, these are just the basic solving function):

const fizzbuzz = x=>[x,f='fizz',b='buzz',f+b][!(x%3)|!(x%5)<<1]
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and:

const fizzBuzz = x=>({1:x,6:f="fizz",10:b="buzz",0:f+b}[x**4%15])
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therickedge profile image
Rithik Samanthula •

Yeah, that's awesome

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dannyengelman profile image
Danny Engelman •

But unreadable and not easy to extend

let FB = Array(100)
  .fill((x, div, label) => x % div ? "" : label)
  .map((func, idx) =>
    func(++idx, 3, "Fizz") + func(idx, 5, "Buzz") || idx
  );
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`