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Discussion on: Daily Challenge #3 - Vowel Counter

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jmc • Edited

Clojure:

;; with regex
(defn vowels [s]
  (count (re-seq #"(?i)[aeiou]" s)))
;; without
(defn vowels [s]
  (count (filter #(some #{%} "AaEeIiOoUu") s)))