defmain():n=4Matrix=generateEmptyMatrix(n)generateMatrix(Matrix,n,0,0,n,n)defgenerateMatrix(matrix,dimension,startRow,startColumn,endRow,endColumn,counter=10,delta=0):ifdimension==1:matrix[startRow][startColumn]=counterreturndisplayMatrix(matrix)ifdimension==2:# GENERATE FIRST ROW
foriinrange(startRow,endRow):matrix[startRow][i]=countercounter+=1# GENERATE LAST ROW
foriinrange(2):matrix[startRow+1][startRow+1-i]=countercounter+=1returndisplayMatrix(matrix)else:# GENERATE FIRST ROW
foriinrange(startRow,endRow):matrix[startRow][i]=countercounter+=1# GENERATE LAST COLUMN
foriinrange(startColumn+1,endColumn):matrix[i][endColumn-1]=countercounter+=1# GENERATE LAST ROW
foriinrange(startRow+1,endRow):matrix[endRow-1][endColumn-1-i+delta]=countercounter+=1# GENERATE FIRST COLUMN
foriinrange(startRow+1,endColumn-1):matrix[endRow-1-i+delta][startColumn]=countercounter+=1returngenerateMatrix(matrix,dimension-2,startRow+1,startColumn+1,endRow-1,endColumn-1,counter,delta+1)
Output when n = 4 (I started my counter at 10 instead of 1):
If it's okay with you, may I add it to the article (with credits to you for the section, of course) so that people can have two different ways of solving the problem in the same place?
An alternative solution using recursion:
Output when n = 4 (I started my counter at 10 instead of 1):
If it's okay with you, may I add it to the article (with credits to you for the section, of course) so that people can have two different ways of solving the problem in the same place?
Yes, it's ok with me
Could you check your DM, please?