This can be done with only the leftPointer. The rightPointer can be deduced from arr.length - leftPointer - 1.
leftPointer
rightPointer
arr.length - leftPointer - 1
Also, isn't Array.prototype.reverse() O(n)? It looks like, as per spec, they do almost the same thing:
Array.prototype.reverse()
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This can be done with only the
leftPointer. TherightPointercan be deduced fromarr.length - leftPointer - 1.Also, isn't
Array.prototype.reverse()O(n)? It looks like, as per spec, they do almost the same thing: