You could simplify your JavaScript solution!
const nums = [0,1,2,3,4,5,6,7,8,9]; const ans = nums .map(num => num*num) .filter(num => num % 2 === 0) .reduce((total, num) => total + num, 0);
I definitely prefer chained expressions c:
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You could simplify your JavaScript solution!
I definitely prefer chained expressions c: