Technically lazy evaluation of a endless stream is iterative, not recursive, but anyway, here is a solution in Haskell:
fibonnaciNums = 0 : 1 : zipWith (+) fibonnaciNums (tail fibonnaciNums) fibonnaci n = last $ take n fibonnaciNums -- or even shorter: fibonnaciNums !! n
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Technically lazy evaluation of a endless stream is iterative, not recursive, but anyway, here is a solution in Haskell: