I just found that 13 + 23 +...+ n3 = (1/4)n2 * (n+1)2
So you would need to reverse that.
m=((1/4)n*(n+1))2 sqrt(m)=(1/4)n*(n+1) //given positive n and m 4*sqrt(m)=n*(n+1)
That's as far as I get in my head
n = 1/2 (sqrt(1 - 8 sqrt(m)) - 1)
Wolfram alpha to the rescue
So my solution would be:
const cubes = m => { let n = (Math.sqrt(1 - 8 * Math.sqrt(m)) - 1)/2; return n === Math.floor(n) ? n : 0; }
That's amazing
But it doesn't work. :( Just tested it after posting.
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I just found that 13 + 23 +...+ n3 = (1/4)n2 * (n+1)2
So you would need to reverse that.
m=((1/4)n*(n+1))2
sqrt(m)=(1/4)n*(n+1) //given positive n and m
4*sqrt(m)=n*(n+1)
That's as far as I get in my head
n = 1/2 (sqrt(1 - 8 sqrt(m)) - 1)
Wolfram alpha to the rescue
So my solution would be:
That's amazing
But it doesn't work. :( Just tested it after posting.