# Avent of Code - Day 02 - Rock Paper Scissors

Advent of Code occurs at Dec 01 to 25 where each day, you will need to solve a puzzle. It is Festival and the problem statement is mostly related to Christmas.

## Day 2 - Rock Paper Scissor Game  ### Q1

``````file1 = open("0.txt", "r")
score = 0

data = {
"X": 1,
"A": 1,
"Y": 2,
"B": 2,
"Z": 3,
"C": 3
}

def win(a, b):
if a == b:
return 0
if a == 1 and b == 2:
return -1
if a == 1 and b == 3:
return 1
if a == 2 and b == 1:
return 1
if a == 2 and b == 3:
return -1
if a == 3 and b == 1:
return -1
if a == 3 and b == 2:
return 1

while True:
if not line:
break
line = line.strip().split()
i, j = line
a, b = data[i], data[j]
if win(b, a) > 0:
score += b + 6
elif win(b, a) == 0:
score += b + 3
else:
score += b

print(score)
``````

### Q2

``````file1 = open("0.txt", "r")

score = 0

data = {
"X": 1,
"A": 1,
"Y": 2,
"B": 2,
"Z": 3,
"C": 3
}

while True:
if not line:
break
line = line.strip().split()
i, j = line
if j == "Y":
score += 3 + data[i]
elif j == "X":
if data[i] == 1:
score += 3
elif data[i] == 2:
score += 1
elif data[i] == 3:
score += 2
elif j == "Z":
if data[i] == 1:
score += 2 + 6
elif data[i] == 2:
score += 3 + 6
elif data[i] == 3:
score += 1 + 6

print(score)
``````

Here is an interesting read: Rock Paper Scissor and Naive Bayes