Discussion on: Know more about function in JavaScript

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Replies for: Okay so you know what to do to make it work, but not why that works. I'll try to explain. To actually display something on the terminal, you need ...

Yeah I see what you mean. But let's look around an another example here. It looks similar to the first one, but when you run thí program, it can run by anyway (although we don't "return" "multiplication()" inside the "callBack()". )

Spyros Argalias • Mar 27 '20

Sorry but I don't fully understand just from the description. Did you have a link to the code? :)

codingTheWorld777 • Mar 27 '20

Oh sorry. Here is the link: repl.it/@doHoangKhanh121/StrikingU...

Spyros Argalias • Mar 27 '20 • Edited

So in this program we're not receiving results or returning anything. We're only printing to the terminal because we use console.log.

Printing to the terminal and returning a result are separate things. One uses console.log and the other uses return.

In this program, we print to the screen on line 7 where we have console.log(${num} * ${i} = ${num * i})

But we never return anything, so on line 17, if we do:

const result = callback(); // this will always be undefined because we're not returning anything from inside callback()

For an example of how return works please see my previous reply :).

Hope that helps :)

codingTheWorld777 • Mar 27 '20

Yep. That really helps me to know more about "return" in function. Thank you very much 🤗

codingTheWorld777 • Mar 27 '20

I am so confused that I don't need to return the "multiplicationTable()" inside "callBack()" to involve the "callBack()" but finally I can receive the result from return of multiplicationTable() @@.