### Topic: Sum square difference

### Problem Statement:

The sum of the squares of the first ten natural numbers is,

```
1^2 + 2^2 + ... + 10^2 = 385
```

The square of the sum of the first ten natural numbers is,

```
(1+2+3...+10)^2 = 55^2 = 3025
```

Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is .

```
3025 - 385 = 2640
```

Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.

You can find the original question here -> Project Euler

## Largest palindrome product - Project Euler Solution

### Deepak Raj ・ Aug 1 '20 ・ 1 min read

### Sum square difference - Project Euler Solution in python

```
def difference(n):
"""
This program will return difference between the square of sum and sum of the square.
"""
sumOfSquare = 0
squareOfSum = 0
for i in range(n+1):
squareOfSum += i
sumOfSquare += i ** 2
return squareOfSum ** 2 - sumOfSquare
if __name__ == "__main__":
print(difference(100))
```

Share Your Solutions for Sum square difference.

## Oldest comments (0)