Ruby Descending Order Method

#ruby #todayilearned

Method takes a non-negative integer (n) as an argument then:

Let me know if you found a better way!

def descending_order(n)
  n.to_s.split("").sort_by {|x| x}.join("").reverse.to_i
end

Top comments (2)

def descending_order(n)
  n.digits.sort_by { |c| -c.ord }.join.to_i
end

This does a few interesting things:

It uses the Integer#digits method, which is effectively the same as int.to_s.chars or int.to_s.split('')
It uses the ord method to get the numeric representation of a character, but negates it to get back to an ascending order, much the same as one would do with a numeric list
join doesn't require '' as it'll assume that.

Granted there are likely better ways to go about it, but this gives some interesting ideas.

I like it thank you!