slight improvement with a short circuit (find vs filter):
find
filter
const twoNumbersEqual = (a, k) => !!a.find(x => a.includes(k-x))
I just realized both of these solutions fail in the case of twoNumbersEqual([5], 10). This can be fixed by passing the index to includes, as such...
twoNumbersEqual([5], 10)
includes
(a, k) => !!a.find((x, i) => a.includes(k-x, i+1))
This should also theoretically be more performant.
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slight improvement with a short circuit (
findvsfilter):I just realized both of these solutions fail in the case of
twoNumbersEqual([5], 10). This can be fixed by passing the index toincludes, as such...This should also theoretically be more performant.