Discussion on: Async function behaves differently in loop [SOLVED]

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Replies for: If you want to use with map, you have to wrap with Promise.all() formatData= async () => { const users = ["rocktimsaikia", "aholachek", "...

Brian Krygsman • Nov 18 '19

(and you might want to await that Promise.all())

Bharath_Bheemireddy • Nov 18 '19 • Edited

Promise.all() waits for all fulfillments (or the first rejection).
developer.mozilla.org/en-US/docs/W...

Brian Krygsman • Nov 18 '19

You're exactly right... and it does so by returning a Promise itself.

Since it returns a Promise, it's await-able in the context of an async function like the code here.

Depends on the expectations of the calling code of course, but if the calling code is expecting the value as opposed to the Promise, it might be worth considering an await

e.g.

//...
const result = await Promise.all(users.map(async (user) => ({
//...