Discussion on: Welcome Thread - v51

Hey @aelmosalamy , I found your fibonacci one-liner solution on Reddit while building the exact same thing. Yours is great! I wanted to achieve this myself without recursion or default parameters, and this is what I came up with:

const fib = n => n > 3 ? [0,1,1,...Array(n-3).fill()].map((e,i,a) => a[i-2] ? ((a[i] = a[i-2] + a[i-1]) || a[i-2] + a[i-1]) : e) : [0,1,1].slice(0,n);

fib(0);  // []
fib(1);  // [0]
fib(3);  // [0, 1, 1]
fib(10); // [0, 1, 1, 2, 3, 5, 8, 13, 21, 34]

Essentially, hijacking the array clone set by the array.prototype.map() function. Thanks for the challenge! 🙌🏼