In which way the word "Reassigning destructured variable" is similar to name.first = ... ? The whole purpose of destructuring is not to use member expression name.first. And yes let { name: { first } } = user is the correct way to use desctructering. user is immutable here. It is important to note that we can pass an object to a function which will not change the original object if function is written correctly using destructering. JavaScript compiler can also optimize it by knowing that the function is pure.
Destructuring in itself doesn't make it immutable. In the example @akashkava
where you re-assigned value to "name" variable and it didn't affect the original object is because the variable of type String (or any other primitives) are immutable and not because it is coming from a destructured object.
Your example is same as
let name = user.name; // string
which makes it immutable because of the data type. @qm3ster
's example showed that destructured values could be mutated which will mutate the origin object.
Destructuring is just syntactic sugar to provide more readability. const name = user.name is same as const { name } = user
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Yes, you assigned the string, so no not by reference. If name itself was an object, it would be by reference yea?
Try it and show me a working example.
Sir, please, there is no need to be rude.
(and yes, you will say to do
const { name: { first } } = user
, but pls. Pls. Sir, pls.)In which way the word "Reassigning destructured variable" is similar to
name.first = ...
? The whole purpose of destructuring is not to use member expressionname.first
. And yeslet { name: { first } } = user
is the correct way to use desctructering.user
is immutable here. It is important to note that we can pass an object to a function which will not change the original object if function is written correctly using destructering. JavaScript compiler can also optimize it by knowing that the function is pure.Destructuring in itself doesn't make it immutable. In the example @akashkava where you re-assigned value to "name" variable and it didn't affect the original object is because the variable of type String (or any other primitives) are immutable and not because it is coming from a destructured object.
Your example is same as
which makes it immutable because of the data type. @qm3ster 's example showed that destructured values could be mutated which will mutate the origin object.
Destructuring is just syntactic sugar to provide more readability.
const name = user.name
is same asconst { name } = user