Here's some recursion. I think it will work, but I'm not sure since I'm on my phone, I'll test it when I get home.
const steps = (n, acc = 0) => n === 1 ? acc : n % 2 === 0 ? steps(n / 2, acc + 1) : steps(n - 1, acc + 1)
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Here's some recursion. I think it will work, but I'm not sure since I'm on my phone, I'll test it when I get home.