Seems like a good problem for regex with backreferences. JavaScript:
function tripledouble(num1, num2) { return /(\d)\1\1.*,.*\1\1/.test(`${num1},${num2}`) ? 1 : 0; }
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re: Daily Challenge #18 - Triple Trouble VIEW POST
FULL DISCUSSIONSeems like a good problem for regex with backreferences. JavaScript: